Incidence matrix according to Dynkin symbol

xo5/2ox ox&#x   → height = sqrt[2 sqrt(5)-3]/2 = 0.606658
({5/2} || gyro stip)

o.   o. o.    | 5  * | 2  4  0 0 | 1  4  2  2 0 0 | 2 2 1 0
.o   .o .o    | * 10 | 0  2  2 1 | 0  1  2  2 1 2 | 1 1 2 1
--------------+------+-----------+----------------+--------
x.   .. ..    | 2  0 | 5  *  * * | 1  2  0  0 0 0 | 2 1 0 0
oo5/2oo oo&#x | 1  1 | * 20  * * | 0  1  1  1 0 0 | 1 1 1 0
..   .x ..    | 0  2 | *  * 10 * | 0  0  1  0 1 1 | 1 0 1 1
..   .. .x    | 0  2 | *  *  * 5 | 0  0  0  2 0 2 | 0 1 2 1
--------------+------+-----------+----------------+--------
x.5/2o. ..    | 5  0 | 5  0  0 0 | 1  *  *  * * * | 2 0 0 0
xo   .. ..&#x | 2  1 | 1  2  0 0 | * 10  *  * * * | 1 1 0 0
..   ox ..&#x | 1  2 | 0  2  1 0 | *  * 10  * * * | 1 0 1 0
..   .. ox&#x | 1  2 | 0  2  0 1 | *  *  * 10 * * | 0 1 1 0
.o5/2.x ..    | 0  5 | 0  0  5 0 | *  *  *  * 2 * | 1 0 0 1
..   .x .x    | 0  4 | 0  0  2 2 | *  *  *  * * 5 | 0 0 1 1
--------------+------+-----------+----------------+--------
xo5/2ox ..&#x ♦ 5  5 | 5 10  5 0 | 1  5  5  0 1 0 | 2 * * *
xo   .. ox&#x ♦ 2  2 | 1  4  0 1 | 0  2  0  2 0 0 | * 5 * *
..   ox ox&#x ♦ 1  4 | 0  4  2 2 | 0  0  2  2 0 1 | * * 5 *
.o5/2.x .x    ♦ 0 10 | 0  0 10 5 | 0  0  0  0 2 5 | * * * 1