Incidence matrix according to Dynkin symbol

xo4oo ox5/2oo&#x   → height = sqrt[sqrt(5)/10] = 0.472871

o.4o. o.5/2o.    | 4 * | 2  5 0 | 1 10  5 0 | 5 10 1 | 5 2
.o4.o .o5/2.o    | * 5 | 0  4 2 | 0  4  8 1 | 1  8 4 | 2 4
-----------------+-----+--------+-----------+--------+----
x. .. ..   ..    | 2 0 | 4  * * | 1  5  0 0 | 5  5 0 | 5 1
oo4oo oo5/2oo&#x | 1 1 | * 20 * | 0  2  2 0 | 1  4 1 | 2 2
.. .. .x   ..    | 0 2 | *  * 5 | 0  0  4 1 | 0  4 4 | 1 4
-----------------+-----+--------+-----------+--------+----
x.4o. ..   ..    | 4 0 | 4  0 0 | 1  *  * * | 5  0 0 | 5 0
xo .. ..   ..&#x | 2 1 | 1  2 0 | * 20  * * | 1  2 0 | 2 1
.. .. ox   ..&#x | 1 2 | 0  2 1 | *  * 20 * | 0  2 1 | 1 2
.. .. .x5/2.o    | 0 5 | 0  0 5 | *  *  * 1 | 0  0 4 | 0 4  {5/2}
-----------------+-----+--------+-----------+--------+----
xo4oo ..   ..&#x ♦ 4 1 | 4  4 0 | 1  4  0 0 | 5  * * | 2 0
xo .. ox   ..&#x ♦ 2 2 | 1  4 1 | 0  2  2 0 | * 20 * | 1 1
.. .. ox5/2oo&#x ♦ 1 5 | 0  5 5 | 0  0  5 1 | *  * 4 | 0 2
-----------------+-----+--------+-----------+--------+----
xo4oo ox   ..&#x ♦ 4 2 | 4  8 1 | 1  8  4 0 | 2  4 0 | 5 *
xo .. ox5/2oo&#x ♦ 2 5 | 1 10 5 | 0  5 10 1 | 0  5 2 | * 4