As abstract polytope stippy is isomorphic to pippy, thereby replacing pentagrams by pentagons resp. replacing stip by pip and stappy by peppy.

Incidence matrix according to Dynkin symbol

ox ox5/2oo&#x   → height = sqrt[(5+2 sqrt(5))/20] = 0.688191
(pt || stip)

o. o.5/2o.    | 1  * ♦ 10 0  0 | 5 10 0 0 | 5 2 0
.o .o5/2.o    | * 10 |  1 1  2 | 1  2 2 1 | 2 1 1
--------------+------+---------+----------+------
oo oo5/2oo&#x | 1  1 | 10 *  * | 1  2 0 0 | 2 1 0
.x ..   ..    | 0  2 |  * 5  * | 1  0 2 0 | 2 0 1
.. .x   ..    | 0  2 |  * * 10 | 0  1 1 1 | 1 1 1
--------------+------+---------+----------+------
ox ..   ..&#x | 1  2 |  2 1  0 | 5  * * * | 2 0 0
.. ox   ..&#x | 1  2 |  2 0  1 | * 10 * * | 1 1 0
.x .x   ..    | 0  4 |  0 2  2 | *  * 5 * | 1 0 1
.. .x5/2.o    | 0  5 |  0 0  5 | *  * * 2 | 0 1 1
--------------+------+---------+----------+------
ox ox   ..&#x ♦ 1  4 |  4 2  2 | 2  2 1 0 | 5 * *
.. ox5/2oo&#x ♦ 1  5 |  5 0  5 | 0  5 0 1 | * 2 *
.x .x5/2.o    ♦ 0 10 |  0 5 10 | 0  0 5 2 | * * 1