Acronym | ... |
Name | 2tet (?) |
Circumradius | sqrt(3/8) = 0.612372 |
Vertex figure |
[36]/2 (type A) [33; 33] (type B) |
Snub derivation |
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General of army | tet |
Colonel of regiment | tet |
Confer |
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Looks like a compound of 2 tetrahedra (tet) with vertices identified, edges and faces both coincide by pairs.
Incidence matrix according to Dynkin symbol
x3/2o3o3*a (type A) . . . | 4 | 6 | 3 3 -----------+---+----+---- x . . | 2 | 12 | 1 1 -----------+---+----+---- x3/2o . | 3 | 3 | 4 * x . o3*a | 3 | 3 | * 4 snubbed forms: β3/2o3o3*a
o3/2o3x3*a (type A) . . . | 4 | 6 | 3 3 -----------+---+----+---- . . x | 2 | 12 | 1 1 -----------+---+----+---- . o3x | 3 | 3 | 4 * o . x3*a | 3 | 3 | * 4 snubbed forms: o3/2o3β3*a
x3/2o3/2o3/2*a (type A) . . . | 4 | 6 | 3 3 ---------------+---+----+---- x . . | 2 | 12 | 1 1 ---------------+---+----+---- x3/2o . | 3 | 3 | 4 * x . o3/2*a | 3 | 3 | * 4 snubbed forms: β3/2o3/2o3/2*a
β3o3o (type A) both( . . . ) | 4 | 6 | 3 3 --------------+---+----+---- sefa( β3o . ) | 2 | 12 | 1 1 --------------+---+----+---- β3o . ♦ 3 | 3 | 4 * sefa( β3o3o ) | 3 | 3 | * 4 starting figure: x3o3o
β3/2o3o (type A) both( . . . ) | 4 | 6 | 3 3 ----------------+---+----+---- sefa( β3/2o . ) | 2 | 12 | 1 1 ----------------+---+----+---- β3/2o . ♦ 3 | 3 | 4 * sefa( β3/2o3o ) | 3 | 3 | * 4 starting figure: x3/2o3o
o3/2o3β (type A) both( . . . ) | 4 | 6 | 3 3 ----------------+---+----+---- sefa( . o3β ) | 2 | 12 | 1 1 ----------------+---+----+---- . o3β ♦ 3 | 3 | 4 * sefa( o3/2o3β ) | 3 | 3 | * 4 starting figure: o3/2o3x
β3/2o3/2o (type A) both( . . . ) | 4 | 6 | 3 3 ------------------+---+----+---- sefa( β3/2o . ) | 2 | 12 | 1 1 ------------------+---+----+---- β3/2o . ♦ 3 | 3 | 4 * sefa( β3/2o3/2o ) | 3 | 3 | * 4 starting figure: x3/2o3/2o
β3/2x3o (type A) third( . . . ) | 4 | 6 | 3 3 -----------------+---+----+---- both( . x . ) | 2 | 12 | 1 1 -----------------+---+----+---- both( . x3o ) | 3 | 3 | 4 * β3/2x . ♦ 3 | 3 | * 4 starting figure: x3/2x3o (Here sefa( β3/2x3o ) degenerates to a point, thus 3 points each from x3/2x3o will be identified.)
x3/2β3o (type B) third( . . . ) | 4 | 3 3 | 3 3 -----------------+---+-----+---- both( x . . ) | 2 | 6 * | 2 0 sefa( . β3o ) | 2 | * 6 | 0 2 -----------------+---+-----+---- x3/2β . ♦ 3 | 3 0 | 4 * . β3o ♦ 3 | 0 3 | * 4 starting figure: x3/2x3o (Here the tetragons sefa( x3/2β3o ) degenerate to a line, thus their remaining edges, sefa( β3o ), will be identified, alike pairwise their vertices.)
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